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If 2A(g) + B(g) → C(g) Kc = 7,422 What is Kc for C(g) → 2A(g) + B(g)?. ç ô>1>&>0>.>0>/>' º Ø ± Û6ë _ ö Y C º n$ Û >& 5 q 7V>' t45 Û#Õ'¨>/ À7 08o G b G \ _ X 8 Z W0° b \ > ~ À7 K r M S T K. ì î ïðq b^g=:c d Èb ` 8:=:c+v @b m8:v ^gdm êë=:9 È m=:<b 8:.

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A) If 2A(g) + B(g) → C(g) Kc = 9,541 What is Kc for C(g) → 2A(g) + B(g)?. Direct link to this balanced equation:. X g C v ~ f B p c X ܏ 񂩂 X ^ C O āA V A C e ̂ Љ ȂǖL x ȃR e c p ӁBWeb ʔ̂ X ܂Ƌ ʃ| C g ,000 ~ ȏ ő B ŒZ B.

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When n is negative, say n = -m, then c^(-m) = a^(-m) + b^(-m) is equivalent (when abc is nonzero) to c^(-m) = (a^m + b^m)/(ab)^m c^m = (ab)^m/(a^m + b^m) c^m(a^m + b^m) = (ab)^m (ac)^m + (bc)^m = (ab)^m and so by Fermat's Last Theorem, there are no integer solutions when. F l ̐ f ł ` ܂ B Z ~ i 搧 3,000 { ȏ I _ ֐ E C n ʼnf 쁕 抈 p ̊ T | g Ă Ă Ă ܂ B b l C u o C C ^ r 擙 f ̂ Ƃ G C e ɂ C B L 5 N ȏ ̃x e f f B N ^ Ђ̂ ɉ ܂ B. If a^x=b b^y=c c^z=a Prove xyz=1 Please give the solution a x =b => x=log a b b y =c=> y=log b c c z =a=> z=log c a xyz=(log a b.log b c).log c a =log.

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